Density and transit in metro Milwaukee
Greater
Milwaukee has had a long and contentious debate about public transit, with one
common argument against investing in rapid transit being that the region doesn't have the population density to support it. A recent study from
the U.S. Census Bureau, however, may be cause for reexamining that contention. It
finds Milwaukee among the densest metropolitan areas in the U.S., with greater
population density than many of the nation’s most populous metros, including Atlanta,
Houston, and Seattle.
In 2010, the
Milwaukee metropolitan area – comprised of Milwaukee, Ozaukee, Washington, and
Waukesha counties – ranked 15th in population density among the 102 metro
areas in the U.S. with populations over 500,000, with a density of 5,258
persons per square mile. Milwaukee was second only to Chicago among Midwest
metros. Notably, the Milwaukee area’s density declined slightly between 2000
and 2010, by 3.6%. This downtick followed a national trend, however, as 33 of
the nation’s 50 largest metro areas saw their densities decline during that
period. The complete data set can be found here.
A
frequently-cited example illustrating why researchers are converting to this
new method of determining population density is the fact that under the
traditional definition, the Los Angeles metro area has a higher density than
the New York metro area, which is counterintuitive to anyone who has visited
both places. Using weighted density, the New York metro is more than twice as
dense as L.A., because the typical New Yorker lives in a denser neighborhood
than the typical Angeleno.
Rapid transit may come back into Greater Milwaukee’s infrastructure planning at some point in the future. While many factors impact the success of a rapid transit system, we now have a clearer understanding of our population density and how it compares with other metro areas around the country.
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